(-9.8t^2)/2+32t=0

Solution for (-9.8t^2)/2+32t=0 equation:

(-9.8t^2)/2+32t=0

We multiply all the terms by the denominator


(-9.8t^2)+32t*2=0

Wy multiply elements

(-9.8t^2)+64t=0

We get rid of parentheses

-9.8t^2+64t=0

a = -9.8; b = 64; c = 0;
Δ = b2-4ac
Δ = 642-4·(-9.8)·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-64}{2*-9.8}=\frac{-128}{-19.6}
=6+7.4285714285715/14
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+64}{2*-9.8}=\frac{0}{-19.6}
=0
$